Posted by **Kay** on Tuesday, May 26, 2009 at 9:38pm.

Enter the balanced chemical equation including states that describes the electrochemical cell that is represented by the cell notation as shown.

Pt(s) | F-(aq) | F2(g) || Cl-(aq), AuCl4-(aq) | Au(s)

I'm having trouble balancing this...

I get AuCl4- + 2F- --> Au + 4Cl- + F2

...but the charges don't cancel out on both sides. The left side has 3- and the right side has 4-. I've been trying to change the numbers around but then I upset the balanced atoms. Help?

- Chemistry - Cell Notation -
**DrBob222**, Wednesday, May 27, 2009 at 12:30am
If you had written them as half cells you would have figured out what to do.

2F^- ==> F2 + 2e

AuCl4^- + 3e ==> Au + 4Cl^-

===========================

Now multiply the fluoride equation by 3 and the Au equation by 2 (to obtain 6e lost and 6e gained) and it will balance.

- Chemistry - Cell Notation -
**Kay**, Wednesday, May 27, 2009 at 12:39am
Thanks a lot! I forgot you had to write the half reactions first.

- Chemistry - Cell Notation -
**Raffi**, Thursday, December 2, 2010 at 8:48pm
HI i WAS WONDERING, which

one was the anode?

- Chemistry - Cell Notation -
**May**, Monday, December 5, 2016 at 7:42am
@Raffi

The Anode is always written first in this notation.

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