Posted by Kay on Tuesday, May 26, 2009 at 9:38pm.
If you had written them as half cells you would have figured out what to do.
2F^- ==> F2 + 2e
AuCl4^- + 3e ==> Au + 4Cl^-
===========================
Now multiply the fluoride equation by 3 and the Au equation by 2 (to obtain 6e lost and 6e gained) and it will balance.
Thanks a lot! I forgot you had to write the half reactions first.
HI i WAS WONDERING, which
one was the anode?
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