Suppose 52 of the students in class have a calculator and 14 have a computer. It is known that 4 do not have either a computer or calc and there are 64 students in the class. Find the probability that a randomly chosen student has a computer AND a calculator.
I know this is an intersection, but don't know how to find the answer. I tried to set up a table, but i have no idea if that would work.
To find the probability that a randomly chosen student has a computer AND a calculator, we can use the concept of set theory and the principle of inclusion-exclusion.
Let's first analyze the given information:
- There are 52 students with a calculator.
- There are 14 students with a computer.
- 4 students do not have either a computer or a calculator.
- There are 64 students in total.
Now, let's find the number of students who have both a computer and a calculator:
TotalStudents = Students_with_calculator + Students_with_computer - Students_with_neither
64 = 52 + 14 - 4
To find the probability, we need to divide the number of students with both a computer and a calculator by the total number of students:
Probability = Students_with_both / TotalStudents
Probability = (52 + 14 - 4) / 64
Calculating this will give you the probability that a randomly chosen student has both a computer and a calculator.