Posted by a girl on Tuesday, May 26, 2009 at 12:36am.
√x2 + 1 + √x2 – 2x + 3 = 3
│ x4 │  │ 2–0,5x│ ≤ 3
│5 x26 │= x25x6
x22x+3 : x24x+3 > 2
Could I get help with solving these please?

Math.  Reiny, Tuesday, May 26, 2009 at 8:48am
You probably got no reply so far since your equations are not clearly stated.
e.g. in the first one, do you mean
√(x^2+1) + √(x^22x3+3) = 3 ?
(the way you have it typed, I could simplify it to 2√(x^2)  2x + 1 = 0 )
If I assumed √(x^2+1) + √(x^22x3+3) = 3
then √(x^22x3+3) = 3  √(x^2+1)
square both sides and simplify to get
6√(x^2 + 1) = 7 + 2x
square again, and solve using the quadratic equation formula.
I got x = (28 ±√2448)/64 or
x = approx. 1.21058 or .3356
(both answers verified in my equation)
for the second, the part shown as │2  0,5x│ has me confused
in the third, is the first part not simply │1  x^2│ ?
In the last is it
(x22x+3) ÷ (x24x+3) > 2 ?
which would be
(x22x+3) / (x24x+3) > 2
Please retype your equations.
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