Physics
posted by Jamie .
A ball is thrown vertically upward with a speed of 1.53 m/s from a point 4.21 m above the ground. Calculate the time in which the ball will reach the ground.
{Distance Above Ground} = D = (4.21) + (1.53)*t + (1/2)*(9.8)*t^2
{D = 0} > {Time To Reach Ground} = 1.096 sec
Is this right?

I didn't check your math, but the equation is right. Do this: put the answer in the google search window to calculate it .
(4.21) + (1.53)*1.096 + (1/2)*(9.8)*(1.096)^2