Posted by **Jamie** on Monday, May 25, 2009 at 5:07pm.

A ball is thrown vertically upward with a speed of 1.53 m/s from a point 4.21 m above the ground. Calculate the time in which the ball will reach the ground.

{Distance Above Ground} = D = (4.21) + (1.53)*t + (1/2)*(-9.8)*t^2

{D = 0} ----> {Time To Reach Ground} = 1.096 sec

Is this right?

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