Posted by **Jamie** on Monday, May 25, 2009 at 5:07pm.

A ball is thrown vertically upward with a speed of 1.53 m/s from a point 4.21 m above the ground. Calculate the time in which the ball will reach the ground.

{Distance Above Ground} = D = (4.21) + (1.53)*t + (1/2)*(-9.8)*t^2

{D = 0} ----> {Time To Reach Ground} = 1.096 sec

Is this right?

## Answer This Question

## Related Questions

- Physics - A ball is thrown vertically upward with a speed of 1.53 m/s from a ...
- Math- - A ball is thrown vertically upward with an initial velocity of 96 feet ...
- physics - a ball is thrown straight up with a speed of 8.0 m/s from a third-...
- Physics - Two students are on a balcony a distance h above the S street. One ...
- Pre-Calculus - A ball is thrown vertically upward with an initial velocity of 64...
- Uniport ( physis) - A ball is thrown vertically upward with a speed v from a ...
- Precalculos - A ball is thrown vertically upward with an initial velocity of 96 ...
- Physics - a tennis ball is thrown vertically upward from the ground and the ...
- Physics - A ball is thrown from a point 1.0 m above the ground. The initial ...
- physics - A ball is thrown from a point 1.38 m above the ground. The initial ...

More Related Questions