Raising rabbits. Before Roland sold two female rabbits,

half of his rabbits were female. After the sale, only onethird
of his rabbits were female. If x represents his original
number of rabbits, then

1
2 �
x � 2 � �
1
3 �
(x � 2).
Solve this equation to find the number of rabbits that he
had before the sale.

I can't read your post.

If x = original number of rabbits, then
(1/2) x = # female rabbits and
(1/2) x = # male rabbits.

Then if Roland sold 2 female rabbits, the number female rabbits now is (1/2)x -2 and that = (1/3)x
So (1/2)x -2 = (1/3)x. Solve for x.
I obtained 12 for the original number of rabbits. Check my thinking. Check my work.

To solve this equation, we'll need to simplify it step by step. Let's break it down and solve it together.

The equation is:

1/2 * x - 2 = 1/3 * (x - 2)

First, let's simplify the equation by multiplying each side by 6 to get rid of the fractions:

6 * (1/2 * x - 2) = 6 * (1/3 * (x - 2))

Simplifying further:

3x - 12 = 2(x - 2)

Now, let's distribute the 2 on the right side of the equation:

3x - 12 = 2x - 4

Next, let's isolate the variables on one side of the equation. To do this, we'll subtract 2x from both sides:

3x - 2x - 12 = -4

Simplifying the equation by combining like terms:

x - 12 = -4

To isolate the variable x, let's add 12 to both sides:

x - 12 + 12 = -4 + 12

Simplifying further:

x = 8

Therefore, the number of rabbits Roland had before the sale is 8.