Posted by **Gemma** on Sunday, May 24, 2009 at 1:07pm.

A turbo-jet flies 50 mph faster than a super-prop plane. If a turbo-jet goes 2000 miles in 3 hours less time than it takes the super-prop to go 2800 miles, find the speed of each plane.

I do not understand how to do this at all. Please explain as well as you can! Thanks.

- Algebra -
**bobpursley**, Sunday, May 24, 2009 at 2:07pm
LEt v be the velocity of the turbo plane, then v-50 is the velocity of the slower. Let t be the time for turbo to go 2000 miles, then t+3 is the time for super .

(velocity*time)= distance

(v-50)(t+3)=2800

and

v*t=2000

From the second equation, t=2000/v, put that into the first equation.

(v-50)(2000/v + 3)=2800

multiply both sides by v

(v-50)(2000+3v)=2800v

multiply it all out, gather terms, and use the quadratic equation.

- Algebra -
**Michelle**, Wednesday, December 11, 2013 at 6:38pm
turbo-jet: 400mph

super-prop: 350mph

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