Posted by maddie on Sunday, May 24, 2009 at 11:36am.
multiply both sides by 35(x+1)(x-3)
then
35(x-3)+35(x+1)=6(x-3)(x+1)
and you should be able to assemble it from there.
so should i just multiply that all out and then plug it in?
Write the two terms on the left with a common denomimnator. Then convert to standard quadratic form.
[(3-x) - (1+x)]/[(1+x)(3-x)] = 6/35
(2-2x)/[(1+x)(3-x)] = 6/35
(1-x) = (3/35)[(1+x)(3-x)]
35 -35x = 3[-x^2 +2x +3)
3x^2 -41x +26 = 0
(3x -2)(x-13)
Check my work. No guarantees
We were lucky that one factored fairly easily. x = 2/3 or 13
i got the same answer but used the quadratic :) thank you for all your help everyone!
Related Questions
algebra II - How do you know if a quadratic equation will have one, two, or no ...
algebra II - How do you know if a quadratic equation will have one, two, or no ...
algebra - Why are there two solutions in the quadratic equation and Why do you ...
Algebra - how to solve this: what is the largest rectangular area that can be ...
college algebra II - using the quadratic equation solve: y^2+16+64=0
algebra II - Solve the quadratic equation 12x^2 + 36a^2= 43ax by factorization ...
Algebra I - What is the quadratic equation? In the standard form of the ...
Algebra - Solve the quadratic equation. 3x^2-15x+18=0 I know that the formula to...
Algebra II - 1)What method(s) would you choose to solve the equation: x2 + 2x - ...
advanced math - Hi, I am trying to solve graphing quadratic equations. One of ...
For Further Reading
