Posted by **Jus** on Saturday, May 23, 2009 at 7:23pm.

Apply algebraic reasoning to show that a=b^(loga/logb) for any a,b>0

- Math -
**bobpursley**, Saturday, May 23, 2009 at 8:17pm
take the log of each side

loga=(loga/logb)logb

now reduce.

- Math -
**Jus**, Saturday, May 23, 2009 at 8:43pm
I have:

loga=(loga/logb)logb

(loga/logb )(1/loga)=logb

(1/logb)=logb

Ok now what?

- Math -
**bobpursley**, Saturday, May 23, 2009 at 10:13pm
you erred.

loga=(loga/logb)logb

the logb on the right side divide out (one on numerator, one in denominator)

loga=loga

divide both sides by loga.

## Answer This Question

## Related Questions

- Math - Apply algebraic reasoning to show that a=b^(loga/logb) for any a,b>0
- Math - 1. Given the product law of logarithms, prove the product law of ...
- Math - Which of the following is not a property of logarithms? A. log(A - B) = ...
- Math Algebra 2 - #4. Express the logarithm in terms of log2M and log2N: log2 1/...
- math/calculus - solve the equation loga(x-5)- loga (x+9)=loga(x-7)-loga(x+9) all...
- math-please help,need quickly - loga(x-5)-loga(x+9)=loga(x-7)-loga(x+9) all the ...
- pre-cal - Change of Base Formula logb x = loga x/loga b to evaluate log14 41. (...
- Math - Properties of Logarithm - Can someone show how to this question. Loga(x+...
- math - of a^2+b^2=2ab, prove log[(a+b)/2]=1/2(loga+logb)
- Algebra help - If loga 8=2.079, loga 5=1.609, and loga 3=1.099, find the ...

More Related Questions