Posted by Jus on .
Apply algebraic reasoning to show that a=b^(loga/logb) for any a,b>0

Math 
bobpursley,
take the log of each side
loga=(loga/logb)logb
now reduce. 
Math 
Jus,
I have:
loga=(loga/logb)logb
(loga/logb )(1/loga)=logb
(1/logb)=logb
Ok now what? 
Math 
bobpursley,
you erred.
loga=(loga/logb)logb
the logb on the right side divide out (one on numerator, one in denominator)
loga=loga
divide both sides by loga.