Posted by Jus on Saturday, May 23, 2009 at 7:23pm.
take the log of each side
loga=(loga/logb)logb
now reduce.
I have:
loga=(loga/logb)logb
(loga/logb )(1/loga)=logb
(1/logb)=logb
Ok now what?
you erred.
loga=(loga/logb)logb
the logb on the right side divide out (one on numerator, one in denominator)
loga=loga
divide both sides by loga.
Related Questions
Math - Apply algebraic reasoning to show that a=b^(loga/logb) for any a,b>...
Math - 1. Given the product law of logarithms, prove the product law of ...
Math - Which of the following is not a property of logarithms? A. log(A - B) = ...
Math Algebra 2 - #4. Express the logarithm in terms of log2M and log2N: log2 1/...
math/calculus - solve the equation loga(x-5)- loga (x+9)=loga(x-7)-loga(x+9) all...
math-please help,need quickly - loga(x-5)-loga(x+9)=loga(x-7)-loga(x+9) all the ...
Math - Properties of Logarithm - Can someone show how to this question. Loga(x+...
Algebra help - If loga 8=2.079, loga 5=1.609, and loga 3=1.099, find the ...
math - of a^2+b^2=2ab, prove log[(a+b)/2]=1/2(loga+logb)
Math Algebra 2 - How do I put log in a TI-84 calculator. #1.Express the ...
For Further Reading
