Posted by Jus on Saturday, May 23, 2009 at 7:23pm.
Apply algebraic reasoning to show that a=b^(loga/logb) for any a,b>0

Math  bobpursley, Saturday, May 23, 2009 at 8:17pm
take the log of each side
loga=(loga/logb)logb
now reduce.

Math  Jus, Saturday, May 23, 2009 at 8:43pm
I have:
loga=(loga/logb)logb
(loga/logb )(1/loga)=logb
(1/logb)=logb
Ok now what?

Math  bobpursley, Saturday, May 23, 2009 at 10:13pm
you erred.
loga=(loga/logb)logb
the logb on the right side divide out (one on numerator, one in denominator)
loga=loga
divide both sides by loga.
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