Posted by Karly on Saturday, May 23, 2009 at 10:42am.
oh wait...should use the 97.5 percentile to get the answer to the 2.5% top students?? because they wouldn't have negative z-scores, right?
Yes, assume a normal distribution.
100 - 2.5 = 97.5%
so any F(z) > .975 gets Summa
My table of z versus F(z) is pretty crude.
for example it has entries
z = 1.9 when F(z) = .971
z = 2.0 when F(z) = .977
We know that somewhere between z = 1.9 and z = 2.0, F (z) = .975
Say maybe any z over 1.95 gets summa.
Now do the same thing for F(z) = 1-.16 = .84
find z for f(z) = .84 (z around 1.0)
any z between there and 1.95 gets cum laude
Yes
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