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March 3, 2015

March 3, 2015

Posted by **katherine** on Friday, May 22, 2009 at 3:31am.

The answer is 460.

I tried finding the magnification for the eyepiece which was m=25/f=25/3.6=6.94.

For the objective lens I tried to solve for q by 1/20 + 1/q = 1/.3 and solved for magnification of objective lens to be m=-q/p.. but i didnt get the correct answer.. is the given value of 20cm=p? i think thats where i went wrong.

- Science -
**Writeacher**, Friday, May 22, 2009 at 8:32amAssistance needed.

Please type your__subject__in the**School Subject**box. Any other words are likely to delay responses from a teacher who knows that subject well.

- objective and eyepiece lens -
**bobpursley**, Friday, May 22, 2009 at 9:27amA resonable approximation for magnification of a microscope is

M= L/f0 * 25/fe

See:http://hyperphysics.phy-astr.gsu.edu/hbasees/geoopt/micros.html

With that approximation, I get

M= 20/.3*25/3.6=463 and it has to be rounded to two sig figures.

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