Posted by annie on Thursday, May 21, 2009 at 9:31pm.
Work done = integral F dx
= 150 x^2/2 + 12 x^4/4
= 75 x^2 + 3 x^4
=75 (2.1)^2 + 3 (2.1)^4
= 389 Joules
= (1/2) m v^2
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