Posted by **kelsi** on Thursday, May 21, 2009 at 9:17pm.

You need to siphon water from a clogged sink. The sink has an area of 0.36 and is filled to a height of 4.0 . Your siphon tube rises 45 above the bottom of the sink and then descends 85 to a pail as shown in the figure. The siphon tube has a diameter of 2.4

A)Assuming that the water level in the sink has almost zero velocity, estimate the water velocity when it enters the pail.

B)Estimate how long it will take to empty the sink

- physics -
**kelsi**, Thursday, May 21, 2009 at 9:19pm
sorry, the units didn't show up. it's .36 m^2, 4.0cm, 45cm, 85cm, 2.4cm

- physics -
**Damon**, Thursday, May 21, 2009 at 9:57pm
water .04 m deep.

volume = .04*.36 = .0144 m^3

bottom of sink to pail height difference is .85-.45 = .4 m

We will have to assume no friction in the pipe or entrance or exit losses unless you know those . Thefore use bernoulli

p + rho g * change in h + (1/2) rho v ^2 = constant

p is air pressure, v at start = 0 so

rho (9.81) (.4) = .5 rho v^2

v^2 = 7.848

v = 2.8 m/s

then

radius = .024/2 = .012 m

pi r^2 = .000452 m^2

so

volume flow rate = 2.8*.000452 = .001267 m^3/s

volume of water = .0144 so

time = .0144/.001267 = 11.36 seconds

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