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December 21, 2014

December 21, 2014

Posted by **Angie** on Wednesday, May 20, 2009 at 5:22pm.

First I made the denominators alike:

-2(2a-1)/(a+2)(2a-1) + 3a(a+2)/(a+2)(2a-1)

= -4a+2/(a+2)(2a+1) + 3a^2+6a/(a+2)(2a-1)

What I want to know is if I can eliminate the a+2 for the first fraction, on both the numerator and the denominator?

- Math -
**bobpursley**, Wednesday, May 20, 2009 at 5:23pmNo. You have to combine numberators first, over a common denominator.

- Math -
**Angie**, Wednesday, May 20, 2009 at 6:09pmthanks

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