Math
posted by Angie on .
In this problem: 2/a+2 + 3a/2a1
First I made the denominators alike:
2(2a1)/(a+2)(2a1) + 3a(a+2)/(a+2)(2a1)
= 4a+2/(a+2)(2a+1) + 3a^2+6a/(a+2)(2a1)
What I want to know is if I can eliminate the a+2 for the first fraction, on both the numerator and the denominator?

No. You have to combine numberators first, over a common denominator.

thanks