Posted by Steve on Wednesday, May 20, 2009 at 1:11pm.
Hi, I have a test tomorrow and our teacher gave us a huge review worksheet. I am still not sure how to do some of these so I would appreciate if you could do the following problems out in all steps. I tried to pick some from each section.
 Thanks :)
1. 7x+2/6x + 2x11/6x
2. x^2/x+5  25/x+5
3. 5/6x2y  3/9x3y
4. x/2x4  2/x^22x
5. x/x+3  5/x+2
6. x4/y^2x2 + x7/x+1

Algebra 1 lvl 1  Steve, Wednesday, May 20, 2009 at 1:13pm
Sorry for number six, the bottom of the first fraction is an x^2 NOT a y^2 very sorry.

Algebra 1 lvl 1  Reiny, Wednesday, May 20, 2009 at 2:25pm
In each case, you should have brackets around what I assume is the numerator and the denominator.
e.g. in #1 (7x+2)/(6x) + (2x11)/(6x)
since you have a common denominator already, just add the tops
= (9x9)/(6x)
= (3x3)/(2x) after dividing top and bottom by 3
#2 becomes (x^225)/(x+5) since we again have a common denominator
= (x+5)(x5)/(x+5) , the top was a difference of squares
= x5
in #3 factor the two denominators to
2(3xy) and 3(3xy)
in the second fraction you can cancel the 3's
and then your common denominator is 2(3xy)
etc
in #4
x/(2x4)  2/(x^22x)
= x/[2(x2)]  2/[x(x2)]
common denominator will be 2x(x2)
so we have
x^2/[2x(x2)]  4/[2x(x2)]
= (x^2  4)/[2x(x2)]
= (x+2)(x2)/[2x(x2)]
= (x+2)/(2x)
do #5 and #6 the same way
in #6 the first denominator factors to
(x2)(x+1), which then becomes your common denominator.
Let me know what you get.

Algebra 1  robert, Friday, July 17, 2009 at 9:52am
3(x2)>4(2x+11)
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