Posted by Matt on Tuesday, May 19, 2009 at 8:06pm.
where is the sine negative?
Isn't it in quadrants III and IV ?
The sine of which angle is 1/2 ?
Isn't it 30º or pi/6 radians
so arcsin (-1/2) is 210º or 330º
which would be 7pi/6 or 11pi/6 radians
Sorry, my mistake. It is arccos, not arcsin. Also, the negative in the book is exactly in the middle. The book just says evaluate the expression.
first of all
-1/2 = 1/-2 = -(1/2)
it makes no difference where the negative sign is
just repeat my steps from above, except use the properties of Cosine
1. the cosine is negative in the 2nd and 3rd quadrants.
2. cos (60 degrees) = cos pi/3 = 1/2
(hint: one of the answers is 2pi/3)
But how do I know where cosine (or tangent and sine) are positive? I don't understand.
Thanks for the help, btw.
It is called the CAST rule
this page explains it well
http://www.worsleyschool.net/science/files/cast/castdiagram.html
It all makes sense now!!!! Thanks, haha.
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