two coins and one six-sided number cube are tosses together.
What probability of getting two heads and a four?
1/24
1/8
2/9
1/12
or
1/9
All three events are independent so
1/6 * 1/2 * 1/2
To find the probability of getting two heads and a four, we need to determine the total number of possible outcomes and the number of favorable outcomes.
First, let's calculate the total number of possible outcomes. When tossing two coins and rolling a six-sided number cube, each coin has two possible outcomes (heads or tails), and the number cube has six possible outcomes (numbers 1 to 6). Since the outcomes of the coins and number cube are independent events, we can multiply the number of possibilities for each to find the total number of outcomes:
Total Number of Outcomes = Number of Coin Outcomes × Number of Coin Outcomes × Number of Number Cube Outcomes
= 2 × 2 × 6
= 24
Now, let's determine the number of favorable outcomes. To get two heads, both coins must land on heads, which has only one possible outcome. To get a four with the number cube, there is only one outcome, which is getting a four.
Number of Favorable Outcomes = Number of Ways to Get Two Heads × Number of Ways to Get a Four
= 1 × 1
= 1
Finally, we can calculate the probability by dividing the number of favorable outcomes by the total number of outcomes:
Probability = Number of Favorable Outcomes ÷ Total Number of Outcomes
= 1 ÷ 24
= 1/24
Therefore, the correct answer is 1/24.