Posted by **MW** on Sunday, May 17, 2009 at 9:28pm.

I need to graph the function,

y = log(root 3)2x

I did...now I need to graph the inverse. What is that?

- Pre Calc -
**Damon**, Sunday, May 17, 2009 at 9:43pm
Are these base 10 logs?

Do you mean

y = log (2x)^(1/3)

?

If so then it

is

y = (1/3) log (2x)

inverse

x = (1/3) log (2y)

3 x = log 2 y

10^(3x) = 2 y

y = (1/2)(1000)(10^x)

y = 500 (10^x)

- Pre Calc -
**MW**, Sunday, May 17, 2009 at 9:55pm
I am sorry, base 3..

log base 3 of (2x)

- Pre Calc -
**drwls**, Monday, May 18, 2009 at 12:58am
y = log(3)2x means that

3^y = 2x, so

x = (1/2)*3^y is the inverse function

You could also write it in inverse function notation as

f^-1(x) = (1/2)*3^x

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