Posted by MW on Sunday, May 17, 2009 at 9:28pm.
I need to graph the function,
y = log(root 3)2x
I did...now I need to graph the inverse. What is that?
Pre Calc - Damon, Sunday, May 17, 2009 at 9:43pm
Are these base 10 logs?
Do you mean
y = log (2x)^(1/3)
If so then it
y = (1/3) log (2x)
x = (1/3) log (2y)
3 x = log 2 y
10^(3x) = 2 y
y = (1/2)(1000)(10^x)
y = 500 (10^x)
Pre Calc - MW, Sunday, May 17, 2009 at 9:55pm
I am sorry, base 3..
log base 3 of (2x)
Pre Calc - drwls, Monday, May 18, 2009 at 12:58am
y = log(3)2x means that
3^y = 2x, so
x = (1/2)*3^y is the inverse function
You could also write it in inverse function notation as
f^-1(x) = (1/2)*3^x
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