Pre Calc
posted by MW .
I need to graph the function,
y = log(root 3)2x
I did...now I need to graph the inverse. What is that?

Are these base 10 logs?
Do you mean
y = log (2x)^(1/3)
?
If so then it
is
y = (1/3) log (2x)
inverse
x = (1/3) log (2y)
3 x = log 2 y
10^(3x) = 2 y
y = (1/2)(1000)(10^x)
y = 500 (10^x) 
I am sorry, base 3..
log base 3 of (2x) 
y = log(3)2x means that
3^y = 2x, so
x = (1/2)*3^y is the inverse function
You could also write it in inverse function notation as
f^1(x) = (1/2)*3^x