Wednesday

April 23, 2014

April 23, 2014

Posted by **Sydney** on Sunday, May 17, 2009 at 3:08pm.

Algebraically solve for 0<phaeta<2pi, 2cos^2 phaeta-7 cos phaeta +3=0

- Math -
**Reiny**, Sunday, May 17, 2009 at 3:31pmallow me to use x instead of 'phaeta' for ease of typing, so

cos^2 x - 7cosx + 3 = 0

(2cosx - 1)(cosx - 3) = 0

cosx = 1/2 or cosx = 3, the latter not possible.

if cosx=1/2,then x = pi/3 or 5pi/3 (60º or 300º)

**Related Questions**

trig - Hi I need to solve this question for x, where 0<x<2pi. The question...

Math - Solve the equation algebraically for x where 0 </ x <2pi. sin (x-(...

MATH - Solve the equation algebraically for x where 0 </ x <2pi. sin x = ...

math 12 - Could you please show me how to solve this question.If 2 cos A-1=0, ...

trig 30 - Please help I need to solve the following question for x, where 0<x...

tri - solve exactly over the indicated interval: 2cos^2(theta)=cos(theta), 0<...

grouping - i am trying to solve for A and B....this question comes from a ...

Trig - If cosx = 10/19 an pi < x < 2pi, find the exact value of cos x/2 ...

Math/Trigonometry - 1. Solve: 2 cos² x - 3 cos x + 1 = 0 for 0 ≤ x < ...

Trig Math - Solve the equation algebraically for x wohere 0 </ x< 2 pi. ...