Tuesday

January 27, 2015

January 27, 2015

Posted by **Sydney** on Sunday, May 17, 2009 at 3:08pm.

Algebraically solve for 0<phaeta<2pi, 2cos^2 phaeta-7 cos phaeta +3=0

- Math -
**Reiny**, Sunday, May 17, 2009 at 3:31pmallow me to use x instead of 'phaeta' for ease of typing, so

cos^2 x - 7cosx + 3 = 0

(2cosx - 1)(cosx - 3) = 0

cosx = 1/2 or cosx = 3, the latter not possible.

if cosx=1/2,then x = pi/3 or 5pi/3 (60º or 300º)

**Answer this Question**

**Related Questions**

trig - Hi I need to solve this question for x, where 0<x<2pi. The question...

Math - Solve the equation algebraically for x where 0 </ x <2pi. sin (x-(...

Math - Solve this equation algebraically: (1-sin x)/cos x = cos x/(1+sin x) --- ...

MATH - Solve the equation algebraically for x where 0 </ x <2pi. sin x = ...

Math - Solving Trig Equations - What am I doing wrong? Equation: sin2x = 2cos2x ...

Trig--check answer - Solve the equation of the interval (0, 2pi) cosx=sinx I ...

Trigonometry - Need help solving problems using the Trigonometric Identities: ...

Math - Solving for Trig Equations - Solve the following equation for 0 less than...

trig 30 - Please help I need to solve the following question for x, where 0<x...

Pre-Calc - Could someone show me how to solve these two problems-I have 10 of ...