Posted by Benjamin on Sunday, May 17, 2009 at 1:23pm.
Let N be the number of nickels and D be the number of dimes. Here is what you know:
N = 4D
10D + 5N = 810
-----------------
Now substitute 4D for N
10D + 20D = 810
30D = 810
You take it from there
30D=810 check
=D=810/30 108*.05+27*.1=8.1
=D=27 5.4+2.7=8.1
8.1=8.1
x=y*4
x=27*4
x=108
y=27
Related Questions
8th Grade Algebra - I need help with these problems: 1) A vending machine takes ...
math algebra 1 - There are 4 times as many nickels as dimes in a coin bag. The ...
algebra - Joseph always throws change into a can and takes it out every two ...
Math - In a collection of nickels, dimes, and quarters worth &6.90, the ...
Algebra 2 - Adding 1 to which digit will increase 736,419 by ten thousand? i ...
8th gr. Algebra - I have 3 math problems for homework that are stumping me. Can ...
Algebra - This is a word problem I am supposed to solve with systems. I am ...
math - John has $2.50 in nickels and dimes in his wallet. He has twice as many ...
Algebra - Use a system of equations to solve problem Emily emptied her bank ana ...
Algebra - Anne has 20 coins in her pocket consisting of nickels and dimes only. ...
For Further Reading