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September 17, 2014

September 17, 2014

Posted by **Clare** on Sunday, May 17, 2009 at 9:52am.

Integrate the differential to find the function z.

Would I say that z was equal to two separate differentials and integrate the first part of the function with respect to x and the second part with respect to y?

z = cosx + x^2 y^2 + x^2 y^2 + C

z = cosx + 2(x^2 y^2) + C

Is this right or have I gone wrong?

- Math -
**bobpursley**, Sunday, May 17, 2009 at 10:55amyou can check..

If z=cosx + 2x^2y^2 + C

then dz/dx= -sinx + 4xy^2 + 4x^2y dy/dx

which is not exactly what you started with.

check my thinking.

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