Posted by **Clare** on Sunday, May 17, 2009 at 9:52am.

dz =(−sinx + 2xy^2)dx +(2x^2 y)dy

Integrate the differential to find the function z.

Would I say that z was equal to two separate differentials and integrate the first part of the function with respect to x and the second part with respect to y?

z = cosx + x^2 y^2 + x^2 y^2 + C

z = cosx + 2(x^2 y^2) + C

Is this right or have I gone wrong?

## Answer this Question

## Related Questions

- Calculus - dy/dx = 4ye^(5x) a) Separate the differential equation, then ...
- calculus 2 - Justify, with a written explanation or a mathematical reasoning ...
- calculus - 1) Integrate Cos^n(x) dx 2) Integrate e^(ax)Sinbx dx 3) Integrate (...
- calculus help please - dy/dx = 2y^2 Integrating...y=2/3 y^3 + C put 1,-1 into ...
- Calculus HELP!!! - Here is the graph. h t t p : / /goo.gl/PTc2I (spaces added at...
- math, calculus 2 - Consider the area between the graphs x+y=16 and x+4= (y^2). ...
- Math - Redo problem 13 from section 1.8 of your textbook (page 62), but use the ...
- Integral calculus - Please do help solve the followings 1) Integrate e^4 dx 2) ...
- Calculus II - How do you integrate the function -- > sinx (4^cosx) from 0 to ...
- Calculus - 6.] Replace the integral in exercise 5 (int. (1/ 1 – t) dt a = 0, b...