Posted by sara on Sunday, May 17, 2009 at 6:43am.
You can factor out some terms.
(x^2-1)/(x-3) * (4x-12)
= [(x+1)(x-1)/(x-3)]*4(x-3)
= 4(x+1)(x-1)
The divisor (x^2 -x -2) can be rewritten
(x-2)(x+1), so the (x+1) terms can also be cancelled out. That leaves you with
4(x-1)/(x-2)
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