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December 18, 2014

December 18, 2014

Posted by **sara** on Sunday, May 17, 2009 at 6:43am.

x^2-1/x-3 * 4x-12/x^2-x-2

- algebra -
**drwls**, Sunday, May 17, 2009 at 7:22amYou can factor out some terms.

(x^2-1)/(x-3) * (4x-12)

= [(x+1)(x-1)/(x-3)]*4(x-3)

= 4(x+1)(x-1)

The divisor (x^2 -x -2) can be rewritten

(x-2)(x+1), so the (x+1) terms can also be cancelled out. That leaves you with

4(x-1)/(x-2)

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