multiply and solve please i need help bad
x^2-1/x-3 * 4x-12/x^2-x-2
You can factor out some terms.
(x^2-1)/(x-3) * (4x-12)
= [(x+1)(x-1)/(x-3)]*4(x-3)
= 4(x+1)(x-1)
The divisor (x^2 -x -2) can be rewritten
(x-2)(x+1), so the (x+1) terms can also be cancelled out. That leaves you with
4(x-1)/(x-2)
To multiply and solve the expression, we can follow these steps:
Step 1: Factorize where possible.
- Let's factorize the numerators and denominators separately.
Numerator 1: x^2 - 1
This can be factored as the difference of squares: (x + 1)(x - 1).
Numerator 2: 4x - 12
We can factor out 4 from this expression: 4(x - 3).
Denominator 1: x - 3
It is already in its simplest form.
Denominator 2: x^2 - x - 2
This can be factored as (x - 2)(x + 1).
Step 2: Simplify the expression.
Now that we have factored the expression, we can simplify it by canceling out any common factors between the numerators and denominators.
The (x - 1) factors cancel out in the numerator and denominator, as well as the (x - 3) factors.
What remains is:
(x + 1) * 4 / (x - 2)(x + 1)
Step 3: Solve for x (if desired).
If you have a specific value of x that you want to solve for, you can set the expression to zero and solve for x. However, since you didn't provide a specific value, we'll leave the expression as is.
So, the simplified expression is:
4 / (x - 2)