Posted by **HELP ME!** on Saturday, May 16, 2009 at 8:40pm.

A pinball machine uses a spring that is compressed 4.0 cm to launch a ball. If the spring constant is 13 N/m, what is the force on the ball at the moment the spring is released?

I don't understand this I guess...

Does the ball leave the spring at the equalbarium position four cm from compression or does it travel past equalbarium and then the ball leaves? Also do I need to know the mass which I know how to do?

Could you please show me how to do this problem and the formulas to use... Thanks for the help

## Answer This Question

## Related Questions

- physics - in preparation in shooting a pinball machine, a spring(k = 675N/m) is ...
- Physics - 5. The ball launcher in a pinball machine has a spring that has a ...
- College Physics - The ball launcher in a pinball machine has a spring that has a...
- physics - A pinball machine launches a 139 g ball with a spring-driven plunger. ...
- Physics - A pinball machine has a spring with spring constant of 125N/m. A 65g ...
- Physics! - A spring with a spring constant of 224.3 N/m is compressed by 0.253 m...
- Physics - A spring with a spring constant of 223.9 N/m is compressed by 0.220 m...
- Physics - A 35.1 g pinball starts at the top of a frictionless pinball table ...
- physics - The spring in the muzzle of a child's spring gun has a spring constant...
- physics - In preparation for shooting a ball in a pinball machine,a spring (K=...

More Related Questions