Posted by NIR on Thursday, May 14, 2009 at 10:10pm.
To raise the received level of your voice by 5.84 dB, the received intensity of your voice must be higher by a factor
10^(5.84/10)= 10^0.584 = 3.837
To acheieve this increase, the distance must decrease by a factor (because of the inverse square law of inteneity)
x = sqrt(3.837) = 1.959
That makes the new distance
1.65/1.959 = 0.842 m
For a review of the subject, see
http://en.wikipedia.org/wiki/Decibel
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