a student collects 400 mL of oxygen at 9.80 kPa. if the tempeture remains constant, what volume would this gas occupy at 9.40 kPa

kPa is pascals right?

yes

volume is inversely prop to pressure:

new volume=400ml * 9.8/9.4

To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature and the amount of gas are constant.

Boyle's Law formula:

P1 * V1 = P2 * V2

Where:
P1 = Initial pressure (9.80 kPa)
V1 = Initial volume (400 mL)
P2 = Final pressure (9.40 kPa)
V2 = Final volume (unknown)

We can rearrange the formula and solve for V2:

V2 = (P1 * V1) / P2

Substituting the given values:

V2 = (9.80 kPa * 400 mL) / 9.40 kPa

Now, let's calculate the final volume:

V2 = (3920 kPa * mL) / 9.40 kPa

Simplifying:

V2 ≈ 417.02 mL

Therefore, the volume of the gas at 9.40 kPa would be approximately 417.02 mL.