Wednesday
July 30, 2014

Homework Help: chem/solubility

Posted by Natash on Wednesday, May 13, 2009 at 11:31pm.

the Ksp of CaF2 = 1.46*10^-10 and Ka of HF = 3.5*10^-4 Calculate the pH of a solution in which the solubility of CaF2 = .0100 moles/liter.

so Ksp =[Ca2+][F-]^2 and
Ka =[H3O+][F-]/[HF]

I'm not sure how to continue...

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