FROM A DISTANCE OF 80 M. THE ANGLE OF ELEVATION OF THE TOP OF A FLAGPOLE IS 18 DEGREES. dETERMINE THE HEIGHT OF THE FLAGPOLE.(NEAREST TETH OF A M.
mY CONFUSION IS ANGLE OF DEPRESSION AND ANGLE OF ELEVATION. mY TECHER CALLS FROM TOP ELEVATION WHILE i INSIST ELEVATION IS FROM THE BOTTOM.
The height is 80 tan 18.
The angle of depression of the observer as seen from the top is the same as the elevation angle of the top as seen by the observer. (Assume the observer's height is zero, or add it to 80 tan 18)
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I understand your confusion. In trigonometry, the terms "angle of elevation" and "angle of depression" are used to refer to the same concept but from different viewpoints.
The angle of elevation is measured when you are looking upwards from a lower point to see an object at a higher point. In your case, you are looking up at the top of the flagpole, so the angle of elevation is appropriate.
On the other hand, the angle of depression is measured when you are looking downwards from a higher point to see an object at a lower point. This scenario doesn't apply to your question since you are not looking down at the flagpole.
To determine the height of the flagpole, we can use trigonometry. Let's use the tangent function:
Tangent(angle) = opposite/adjacent
In your case:
Tangent(18 degrees) = height of the flagpole/80m
To solve for the height of the flagpole:
height of the flagpole = 80m * Tangent(18 degrees)
Now, let's calculate it using Tangent(18 degrees):
Tangent(18 degrees) ≈ 0.32492
Therefore, the height of the flagpole is approximately:
height of the flagpole = 80m * 0.32492 ≈ 25.99m
Rounding to the nearest tenth, the height of the flagpole is approximately 26.0 meters.