Posted by Kay on Wednesday, May 13, 2009 at 1:38pm.
I tried drawing it out and got nowhere.
The straight line part I have ok. On carbon 2 I assume you are saying there asre TWO CH3 groups. That's ok. But I have trouble on #4 and #5. If I put CH3CH3 and CH3 I interpret that as three CH3 groups and that means that C has more than four bonds which is a no, no. You may have meant for the CH3CH3 to be CH3CH2 and a CH3. That would make #4 ok to have both a methyl and an ethyl group attahed. #5 is a mystery. It has a CH3CH@ which doesn't mean anything to me. Perhaps you meant CH3CH2 and a CH3. I assume you have made some typos. Please check the post and make any corrections necessay and I can help you name it.
The CH@ is supposed to be CH2. And I didn't write the numbers to be the parent chain. I just numbered them so it would be easier for me to explain. On #4, there's one on top and 2 on bottom. #5, they're all on bottom.
I also think the parent chain has 8 carbons in it. So I know the name ends in octane.
I don't have it. Here is what I have.
CH3C(CH3)2CH2C(CH3)(C2H5)CH(CH3)CH2CH3
which makes a chain of seven if I have interpreted what you have written correctly. If that isn't correct, try rewriting the formula in a straight line as I have done.
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