Posted by Jane on Tuesday, May 12, 2009 at 2:59pm.
There must be such a formula, but it will depend upon how many digits are in the number, and what the initial digits are.
From n = 0 to 9, if n is the largest number, the sum of digits is
n(n+1)/2
From n = 10 to 19, in n is the largest number and you include the sum for digits for 1 though 9, the sum is
45 + (n-9) + (n-10)(n-9)/2
For n = 20 to 29, the sum is
55 + 2(n-19) + (n-20)(n-19)/2
And it keeps getting messier.
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