Posted by **Sarah** on Tuesday, May 12, 2009 at 2:44pm.

(2,14),(1,-1),(3,35)

Find the quadratic function y=ax^2+bx+c

1) 4a+2b+c=14

2) a+b+c=-1

3) 9a+3b+c= 35

equation 1&2 = 3a + b = 13

equation 1&3 = -5a +5b = -21

i know you take those two equations now

3a + b = 13

-5a - 5b = -21

multiply the top by 5 and the bottom equation by 3

15a + 5b = 65

-15a - 15b = -63

that

-10b = 2

but its suppose to come out to a whole number what am i doing wrong???

## Answer This Question

## Related Questions

- Algebra2 - Find the polynomials roots to each of the following problems: #1) x^2...
- Math - I can't remember how you find the roots of quadratic equations other than...
- math - Still looking at how to solve these... Both are cubic polynomials? 43x^3...
- College Algebra - Solve the system of equations with ROWOPS program. I know how ...
- QUADRATIC EQUATION - r^2+8r=48 First bring the 48 to the other side of the ...
- math - Still having problems solving this... 2x(2x + 1)^2 = 312 I started with: ...
- algebra II - How do you know if a quadratic equation will have one, two, or no ...
- algebra II - How do you know if a quadratic equation will have one, two, or no ...
- algebra - solve for x (24+2x)(10+2x) - 240 = 152 First multiply. 24(10) = ___ 2x...
- Algebra, Solving equations - I'm stuck with this equation: y = (4x-1)/(2x+3) We'...

More Related Questions