use substitution method for solving
x+y=4
(x+2)^2+(y-3)^2=5
I got the first part to solve it
x +y =4
y=4-x
the second part i got to
(x+2)^2 + ((4-x)-3)^2=5
x^2 + 2x + 2 ((4-x)-3)^2 = 5
and that is all i could get that i knew was right but i don't know how to get the solutions
