On the topic of esters, if my Ester is
CH3-C(double bond directly downward below the C)-O-CH3, would it be methyl ethanoate or methanoate ethyl? Thanks.
You name the alcohol group first and the acid group second. The alcohol group in this case is methyl. Then you count the C atoms, including the C attached to the =O and name it as an -oate. So the name is methyl ethanoate (the acid CH3COOH is ethanoic acid)
To determine the correct name for the given ester (CH3-C(double bond directly downward below the C)-O-CH3), we need to consider the naming rules for esters.
The ester name is derived from the alcohol part of the compound followed by the acid part. The alcohol portion is named using the alkyl group connected to the oxygen, while the acid portion is named using the parent carboxylic acid.
In this case, there are two carbons connected to the oxygen, which corresponds to an ethyl group (C2H5-) for the alcohol portion. The remaining carbon bonded to the double-bonded oxygen is part of the carboxylic acid, which is an ethanoic acid.
Therefore, the correct name for the given ester is ethyl ethanoate.
To derive the name, you first identify the alkyl group connected to the oxygen, which is ethyl (C2H5-). Then, you identify the parent carboxylic acid, which is ethanoic acid (CH3-COOH). Finally, you combine the two parts, resulting in the name ethyl ethanoate.
Remember to always consider the IUPAC naming rules to ensure a correct and systematic naming of organic compounds.