Posted by TALITA on Monday, May 11, 2009 at 2:07pm.
Factor each one into their primary factors 5 & 2 & 2, 2 & 3 & 5, and finally 2 & 5 & 5.
Does that answer your question? Thanks for asking.
Another way to solve this problem is to list each of the multiples:
20, 40, 60, 80, 100, 120, 140, 160, 180, 200, 220, 240, 260, 280, 300, 320, 340, 360
30, 60, 90, 120, 150, 180, 210, 240, 270, 300, 330, 360
50, 100, 150, 200, 250, 300, 350
What is the smallest number that's the same on all three lists?