Thursday

November 27, 2014

November 27, 2014

Posted by **Annie** on Sunday, May 10, 2009 at 9:06pm.

- calculus -
**drwls**, Sunday, May 10, 2009 at 11:52pmdy = (3x)/(1-x^2) dx

y = Integral of [3x/(1-x^2)] dx + constant

For the integration, let

1-x^2 = u

-2x dx = du

Which make the integral

Integral of (-3/2)du/u = -(3/2)ln(1-x^2)

**Answer this Question**

**Related Questions**

Math - Hello I am having trouble with a pre-calculus problem. The problem is ln|...

Functions - What's the best way to solve functions? I can do basic ones, but ...

Math - I am having trouble remembering how to simplify fractions

Math - i have my final tomorrow and this question was on my review? im having ...

Algebra 1 Question - How would you solve 50 + 9x - 19x = -9 (X= ) I'm just ...

calculus - I am studying for a final exam and in our review packet we have this ...

Functions - more info - Sorry, I forgot to enter all the info before. Below is ...

Math - I asked this question yesterday, but I am still having alot of trouble, ...

IST 423 Networking - I have a study sheet for an upcoming exam and I'm having ...

Chem I - Are there any tricks for remembering solubility rules? I am having a ...