Posted by Annie on Sunday, May 10, 2009 at 9:06pm.
I am having alot of trouble remembering how to do this and this is a practice question for my final if you could help that would be great. Solve the differential equation (dy/dx)=(3x)/(1x^2)

calculus  drwls, Sunday, May 10, 2009 at 11:52pm
dy = (3x)/(1x^2) dx
y = Integral of [3x/(1x^2)] dx + constant
For the integration, let
1x^2 = u
2x dx = du
Which make the integral
Integral of (3/2)du/u = (3/2)ln(1x^2)