Saturday

March 28, 2015

March 28, 2015

Posted by **Annie** on Sunday, May 10, 2009 at 9:06pm.

- calculus -
**drwls**, Sunday, May 10, 2009 at 11:52pmdy = (3x)/(1-x^2) dx

y = Integral of [3x/(1-x^2)] dx + constant

For the integration, let

1-x^2 = u

-2x dx = du

Which make the integral

Integral of (-3/2)du/u = -(3/2)ln(1-x^2)

**Answer this Question**

**Related Questions**

Calculus - I'm having trouble with part of a question in a problem set. The ...

Functions - What's the best way to solve functions? I can do basic ones, but ...

Math - Hello I am having trouble with a pre-calculus problem. The problem is ln|...

Calculus - Solve the differential equation dy/dx = -xe^y and determine the ...

Calculus - Solve the differential equation. t(dy/dt) + 2y= t^3 t>0, y(1)=0 I ...

Pre-Calculus - I am having trouble with several problems: 1) Find the ...

Pre-Calculus - I am having trouble with several problems: 1) Find the ...

PLEEEEEAAAASE HELP WITH DIFFERENTIAL EQ PROBLEMS!! - 1) What are the equilibrium...

Functions - more info - Sorry, I forgot to enter all the info before. Below is ...

Calculus - How would you solve this differential equation? dy/dx=1/2x+y-1