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December 19, 2014

December 19, 2014

Posted by **Kamath** on Sunday, May 10, 2009 at 2:35pm.

f(x)=1/5(x+7)^2+7

I need to find the vertex line of symmetry max/min and is the value f(-7)=7 a minimum or a maximum?

- algebra I need immediate help with this question T -
**Damon**, Sunday, May 10, 2009 at 2:57pmYou typed that so I am not sure what you mean.

y = (1/5) (x+7)^2 + 7

or

y = 1/[5(x+7)^2] + 7

I will assume the first.

then

(y-7) = (1/5)(x+7)^2

when x = -7 (the axis of symmetry), the right is zero so y = 7

as x gets big or very negative, y gets big so parabola faces up (holds water).

Therefore the vertex at (-7,7) is a minimum

- To Damon -
**Kamath**, Sunday, May 10, 2009 at 3:04pmThanks so much I just looked at my answers and I realized I had gotten the right answers after all. Many thanks

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