Monday

July 28, 2014

July 28, 2014

Posted by **krystal** on Sunday, May 10, 2009 at 7:07am.

The first question is

f(x)=-2x^2 + 2x + 8

I need to find the x and y coordinates of the vertex the line of symmetry and the max/min of f(x)

also the value of f(1/2) =17/2

The 2nd question has a fraction and I think this is confusing me on this one

f(x)=1/5(x+7)^2+7

I need to find the vertex line of symmetry max/min and is the value f(-7)=7 a minimum or a maximum?

- algebra urgently need help -
**Damon**, Sunday, May 10, 2009 at 11:05am-2x^2 + 2x + 8 = y

x^2 - x - 4 = -y/2

x^2 - x = -(1/2) y + 4

x^2 - x + 1/4 = -(1/2) y + 4 1/4

(x-1/2)^2 = -(2/4)y - 17/4

(x-1/2)^2 = -(2/4)(y - 8.5)

so

symmetric about the line x = 1/2

and the vertex is on that vertical line

at y = 8.5

so

vertex point = (1/2, 8.5)

LOL, we already know f(1/2) is 17/2 = 8.5

The parabola is upside down (sheds water , so the vertex is at the maximum.

Check that:

If x = 1/2 then

y = -2 (1/2)^2 +2(1/2) + 8

= -1/2 +1+8 = 8.5 check

- algebra tahnks to damon -
**krystal**, Sunday, May 10, 2009 at 11:35amcan you help with the 2nd question? I have stressed myself over this and I am frustrated. I appreciate you help so much

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