Posted by Jon on .
A jet leaves a runway whose bearing is N26E from the control tower. After flying 4 miles, the jet turns 99 degrees and flies on a bearing of s55e for 6 miles. At that time what is the bearing from the jet from the control tower. I have no idea how to solve this please help!
college math -
How far did the jet go North?
4 cos 26 - 6 cos 55
= .1537 north of origin
How far did the jet go East?
4 sin 26 + 6 sin 55
= 6.67 east of origin
tan angle north of east = .1537/6.67
angle North of East = 1.32 degrees
angle East of North = 90 - 1.32 = 88.7 degrees.
That is from the control tower to the Jet
You have a typo and I can not tell which is from and which is to.
from the jet TO the control tower would be
South 88.7 West