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Posted by on Saturday, May 9, 2009 at 12:06am.

A solution of AgNO3 contains 29.66 g of solute in 100.0 mL of solution. What is the molarity of the solution?

  • chemistry help - , Saturday, May 9, 2009 at 12:29am

    moles = grams/molar mass.
    M = moles/L of solution.

  • chemistry help - , Saturday, May 9, 2009 at 12:33am

    29.66/100.0=.2966 molar mass

    i don't know where to go from here.

  • chemistry help - , Saturday, May 9, 2009 at 12:45am

    The molar mass of AgNO3 is not 100. Add up atomic mass Ag, N, and three O atoms to get the molar mass (the periodic tab le will give you the atomic masss).
    Then 29.66 g/molar mass = moles AgNO3.
    Then moles AgNO3/liters of soln= M.
    (They tell you the solution is 100 mL. That's 0.100 L.

  • chemistry help - , Saturday, May 9, 2009 at 5:37am

    Molecular weight os AgNO3 = 169.87
    You have 29.66 g, therefore you have 29.66 / 169.87 moles = 0.174 moles. This is in 100 ml. Molarity is moles per liter, so, 0.174 x (1000/100) = 1.75. Concentration of the solution = 1.75 M. Worked out with chemCal for the iPhone/iPod Touch.

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