Posted by Nguyen on Friday, May 8, 2009 at 10:32pm.
Remember for any type of address the first address 00000000(0) and last address 11111111(255) are not used, therefore first host address begins with 1 and last usuable host is 254 same goes for the subnet address.
Solution:
a)10000000.10101011.00000001.00000001
b)128.171.1.1
c)10000000.10101011.00000011.00000010
d)128.171.3.2
e)10000000.10101011.00000011.11111110
f)128.171.3.254
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