Posted by HELP ME! on Friday, May 8, 2009 at 7:51pm.
Well I'm curently taking this class as a sophmore and have taken geometry freshmen year of high school and also I am taking physics at the same time and in math class when I'm asked to factor i go absolutley nuts because guessing numbers is just no my thing... I need solve for X rearange formulas and so forth...
with that said is this legal?
X^2 + 3X + 4
factor that...
(X^2 + 3X + 4)^(1/2)
factored form
(X + (3X)^(1/2) + 2)^2
I believe this is perfectly acceptable for factoring but I'm not sure...
my textbook says that the agreement for completely factored from is..
A polynomial is completely factored when it is written as a product of tow or more polynomilas with integers for their coefficients.
So I believe I can leave that as a factored form correct?

Algebra 2  bobpursley, Friday, May 8, 2009 at 8:31pm
no.
(x^2+3x+4). What multiplys to 4 and adds to three? Nothing. There are no factors. If the 4 were negative, then 4,1 would be the factors (x+4)(x1), but that is not the case.
You need to learn how to factor, it is not a guessing game.

Algebra 2  drwls, Friday, May 8, 2009 at 8:42pm
The square root of a polynomial is not the sum of the square roots of each term. It just doesn't work that way.
If you are trying to factor
x^2 + 3x + 4, there are no simple monomial factors with integer constants. The roots are complex,
[3 +/ sqrt7i]/2 and 1.5 +/ 2.6458i
The factors are
(x+1.52.6458i)(x+1.5+2.6458i)
where i is the square root of 1

Algebra 2 (correction)  drwls, Saturday, May 9, 2009 at 7:49am
The roots are complex,
[3 +/ isqrt7]/2 = 1.5 +/ 1.3228i
The factors are
(x+1.51.3228i)(x+1.5+1.3228i)
where i is the square root of 1

Algebra 2  derr, Saturday, April 17, 2010 at 4:25pm
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