Posted by **HELP ME!** on Friday, May 8, 2009 at 7:51pm.

Well I'm curently taking this class as a sophmore and have taken geometry freshmen year of high school and also I am taking physics at the same time and in math class when I'm asked to factor i go absolutley nuts because guessing numbers is just no my thing... I need solve for X rearange formulas and so forth...

with that said is this legal?

X^2 + 3X + 4

factor that...

(X^2 + 3X + 4)^(1/2)

factored form

(X + (3X)^(1/2) + 2)^2

I believe this is perfectly acceptable for factoring but I'm not sure...

my textbook says that the agreement for completely factored from is..

A polynomial is completely factored when it is written as a product of tow or more polynomilas with integers for their coefficients.

So I believe I can leave that as a factored form correct?

- Algebra 2 -
**bobpursley**, Friday, May 8, 2009 at 8:31pm
no.

(x^2+3x+4). What multiplys to 4 and adds to three? Nothing. There are no factors. If the 4 were negative, then 4,-1 would be the factors (x+4)(x-1), but that is not the case.

You need to learn how to factor, it is not a guessing game.

- Algebra 2 -
**drwls**, Friday, May 8, 2009 at 8:42pm
The square root of a polynomial is not the sum of the square roots of each term. It just doesn't work that way.

If you are trying to factor

x^2 + 3x + 4, there are no simple monomial factors with integer constants. The roots are complex,

[-3 +/- sqrt7i]/2 and -1.5 +/- 2.6458i

The factors are

(x+1.5-2.6458i)(x+1.5+2.6458i)

where i is the square root of -1

- Algebra 2 (correction) -
**drwls**, Saturday, May 9, 2009 at 7:49am
The roots are complex,

[-3 +/- isqrt7]/2 = -1.5 +/- 1.3228i

The factors are

(x+1.5-1.3228i)(x+1.5+1.3228i)

where i is the square root of -1

- Algebra 2 -
**derr**, Saturday, April 17, 2010 at 4:25pm
2pie16

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