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April 20, 2014

April 20, 2014

Posted by **trig** on Friday, May 8, 2009 at 2:54pm.

Ok, my result is that there is no intersection point because if you put f(x)=g(x) and try to solve for x or the intersection point, the LS f(x) is not possible, so there is none?

OK can someone just clarify for me if I have this right? Explain please thanks!

- Anonymous -
**bobpursley**, Friday, May 8, 2009 at 3:52pmset them equal

2cos^2x-4sinx+11=4sin^2x+7sinx+6

2-2sin^2x-4sinx+11=4sin^2x+7sinx+6

-6sin^2x-11sinx+7=0

check that.

(3sinx+7)(-2sinx+1)=0

sinx=-7/3 not possible

sinx=1/2 x=330deg

check.

f(x)=4(1/4)+7(1/2)+6=10.5

g(x)=2(3/4)-4(1/2)+11=10.5

check me

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