Posted by **cl** on Friday, May 8, 2009 at 1:11pm.

here is my source code for my program im trying to convert 10 units from furlong to meters the answer is supposed to be 2011.68 meters

i keep getting 2000. I know if i cant get this right the rest of the conversion will give the wrong answers anybody have any ideas?

Dim inch As Long

Dim fathom As Long

Dim foot As Long

Dim furlong As Long

Dim kilometer As Long

Dim meter As Long

Dim rod As Long

Dim miles As Long

Dim yard As Long

Dim Feet As Long

Dim Original As Long

Dim Desired As Long

Dim A(0 To 9) As Long

Dim B(0 To 9) As Long

Dim result As Long

Private Sub convertButton_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles convertButton.Click

Feet = Val(ConvertText.Text)

Original = Val(OUnitsTexT.Text)

Desired = Val(DUnitsText.Text)

inch = 0.0833 * Feet

yard = 3 * Feet

meter = 3.28155 * Feet

fathom = 6 * Feet

rod = 16.5 * Feet

furlong = 660 * Feet

kilometer = 3281.5 * Feet

miles = 5280 * Feet

A(1) = inch

A(2) = fathom

A(3) = foot

A(4) = furlong

A(5) = kilometer

A(6) = meter

A(7) = miles

A(8) = rod

A(9) = yard

B(1) = inch

B(2) = fathom

B(3) = Feet

B(4) = furlong

B(5) = kilometer

B(6) = meter

B(7) = miles

B(8) = rod

B(9) = yard

result = ((A(Original)) / ((B(Desired)) / Feet))

lengthText.Text = Val(result)

lengthText.Text = FormatNumber(result, 2, , , TriState.True)

- visual basic -
**SraJMcGin**, Friday, May 8, 2009 at 2:41pm
I only know that taking this Conversion Chart, entering 6600 feet and changing to meters, I do get 2022.68.

http://www.sciencemadesimple.com/length_conversion.php

This is definitely not my area so I can not help you set up a formula, if that is what you need.

Sra

- visual basic -
**RickP**, Friday, May 8, 2009 at 7:04pm
The problem MIGHT be here.

result = ((A(Original)) / ((B(Desired)) / Feet))

Some languages (like C and C++) do integer division unless you explicitly make it do "normal" division. In other words, if you do 5/2 in C the result will be the integer 2, not the "floating point number" 2.5.

- visual basic -
**RickP**, Friday, May 8, 2009 at 7:08pm
I just figured it out: It's simpler than that.

You are declaring all of your numeric variables a LONG. LONG is an integer data type: it does not store anything to the right of a decimal point.

Try using DOUBLE (or better, DECIMAL, if your version supports it) for any numbers you need to have values to the right of the decimal point.

## Answer this Question

## Related Questions

- visual basic - Doing a units of measurement program dont know what the formula i...
- Programming - Here is the question that I need help to write the code for the ...
- physics - You are standing 7.0 meters from a sound source that radiates equally ...
- PROGRAMMING - PLS, I NEED TO BE GUIDED ON HOW TO WRITE A SIMPLE PROGRAM IN BASIC...
- Physics - PLEASE HELP, I'm trying to study for a quiz >.< and I don't ...
- C++ program - Please help am not very good at c program. Am supposed to create a...
- Programming (Visual Basic) - Im seem to be having trouble with this Exercise. ...
- visual basic - in visual basic, notes in a program which explain what the ...
- Programming - How would the flow charts and pseudocode look for this? The Metric...
- Geometry - Can you check these multiple choice questions thanks. 1. What is the ...

More Related Questions