Please check your previous posts in the last couple of days. I thought someone had already answered this question.
They're the same type of questions, but they're different equations.
put in any old x, find y
For example x = 100
400 - 3 y = 6
3 y = 394
y = 131 1/3
(6, 131 1/3)
I'm not a math teacher -- but how about setting up a table with the multiples of 4 and the multiples of 3.
4, 8, 12, 16, 20, 24, etc.
3, 6, 9, 12, 15, 18, 21, 24, etc.
Which numbers -- when subtracted -- he 6?
Oh, you want whole number solutions?
The slope of this line is 4/3
so from your first point (3,2)
go right 3 and up 4
again go right 3 and up 4
(0,-2) up 4 over 3 = (3,2)
(3,2) up 4 over 3 = (6,6)
(6,6) up 4 over 3 = (9,10)
Thanks, all of you!!
Please save this post so that you'll have several methods for solving similar problems.
If you cannot learn the GENERAL PROCESS, then you need to be taught the same general thing a million different times.
You need to learn how to abstract ideas and then apply them to specific instances.
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