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August 28, 2015
Posted by **mysterychicken** on Thursday, May 7, 2009 at 5:01pm.

Find three ordered pairs for the given equation:

4x - 3y = 6

I got one: (3,2)

I need help on this ASAP!! Thankss

-MC

- Pre-Algebra [repost] -
**Ms. Sue**, Thursday, May 7, 2009 at 5:03pmPlease check your previous posts in the last couple of days. I thought someone had already answered this question.

- Pre-Algebra [repost] -
**mysterychicken**, Thursday, May 7, 2009 at 5:45pmThey're the same type of questions, but they're different equations.

-MC

- Pre-Algebra [repost] -
**Damon**, Thursday, May 7, 2009 at 5:48pmput in any old x, find y

For example x = 100

400 - 3 y = 6

3 y = 394

y = 131 1/3

(6, 131 1/3)

- Pre-Algebra [repost] -
**Ms. Sue**, Thursday, May 7, 2009 at 5:50pmOK.

I'm not a math teacher -- but how about setting up a table with the multiples of 4 and the multiples of 3.

4, 8, 12, 16, 20, 24, etc.

3, 6, 9, 12, 15, 18, 21, 24, etc.

Which numbers -- when subtracted -- he 6?

- Pre-Algebra [repost] correction -
**Ms. Sue**, Thursday, May 7, 2009 at 5:51pm*equal 6

- Pre-Algebra [repost] correction -
- Pre-Algebra [repost] -
**Damon**, Thursday, May 7, 2009 at 6:05pmOh, you want whole number solutions?

The slope of this line is 4/3

so from your first point (3,2)

go right 3 and up 4

(6,6)

again go right 3 and up 4

(9,10)

- Pre-Algebra [repost] -
**Bob**, Thursday, May 7, 2009 at 6:16pmy=4/3x-2

m=4/3=slope

(0,-2) up 4 over 3 = (3,2)

(3,2) up 4 over 3 = (6,6)

(6,6) up 4 over 3 = (9,10)

- Pre-Algebra [repost] -
**mysterychicken**, Thursday, May 7, 2009 at 6:50pmThanks, all of you!!

-MC

- Pre-Algebra [repost] -
**Ms. Sue**, Thursday, May 7, 2009 at 7:15pmYou're welcome.

Please save this post so that you'll have several methods for solving similar problems.

- Pre-Algebra [repost] -
**RickP**, Thursday, May 7, 2009 at 10:43pmIf you cannot learn the GENERAL PROCESS, then you need to be taught the same general thing a million different times.

You need to learn how to abstract ideas and then apply them to specific instances.