Help me divide and simplify this problem
2z-6/77 divided by z-3/33z
grateful for the help
Notice that 2z-6 is the same as 2(z-3)
I have gotten the answer 6z/7 and the guidance you gave me indicates that this is most likely the answer. Thank you
To simplify the expression, "2z - 6/77 divided by z - 3/33z," you can follow these steps:
Step 1: Divide the numerator by the denominator to simplify the division of fractions:
(2z - 6/77) ÷ (z - 3/33z)
Step 2: Factorize the denominators, if possible:
77 = 7 * 11
33z = 3 * 11 * z
Step 3: Rewrite the expression with the factored denominators:
(2z - 6)/(7 * 11) ÷ (z - 3)/(3 * 11 * z)
Step 4: Invert the second fraction and multiply:
(2z - 6)/(7 * 11) * (3 * 11 * z)/(z - 3)
Step 5: Cancel out common factors:
(2z - 6)/(7) * (3)/(z - 3)
Step 6: Simplify further:
(2z - 6)(3)/(7(z - 3))
Step 7: Distribute and combine like terms:
(6z - 18)/(7(z - 3))
The simplified expression is (6z - 18)/(7z - 21).
Therefore, the answer to the expression "2z - 6/77 divided by z - 3/33z" is (6z - 18)/(7z - 21).