Thursday
April 17, 2014

Homework Help: calculus

Posted by XCS on Thursday, May 7, 2009 at 10:43am.

Could someone check my reasoning? thanx

Find the derivative of the function.

sin(sin[sinx])

I need to use the chain rule to solve. So I take the derivative sin(sin[sinx) first. Then multiply that by the inside which is the derivative of sin[sinx]. And multiply that by derivative of [sinx].

So this is what I got:

cos(sin[sinx])*cos[sinx]*cosx

Is this right?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Calculus - Can someone help me find the derivatives of these questions? For ...
Calculus grade 12 - Determine the derivative of each function A1) y = e^x(Sinx...
Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...
Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...
trig!! - Sin(X-y)sin(x+y)=sin^2 x - sin^2 y work on one side only...so i worked ...
Trig - Sin(X-y)sin(x+y)=sin^2 x - sin^2 y work on one side only...so i worked on...
Calculus - Consider the function f(x)=sin(1/x) Find a sequence of x-values that ...
Calculus I - Find the derivative of f(x) = sin^2 (e^sin^2 x) I wonder if I'm ...
Math, Calculus - Find the derivative of the function. y= xcosx - sinx What's the...
Trig Help - Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx...

Search
Members