Saturday

March 28, 2015

March 28, 2015

Posted by **XCS** on Thursday, May 7, 2009 at 10:43am.

Find the derivative of the function.

sin(sin[sinx])

I need to use the chain rule to solve. So I take the derivative sin(sin[sinx) first. Then multiply that by the inside which is the derivative of sin[sinx]. And multiply that by derivative of [sinx].

So this is what I got:

cos(sin[sinx])*cos[sinx]*cosx

Is this right?

- calculus -
**Count Iblis**, Thursday, May 7, 2009 at 11:07amCorrect.

**Answer this Question**

**Related Questions**

Calculus Help and Check - find the derivative of the function integral from cosx...

Calculus - Can someone help me find the derivatives of these questions? For ...

Math Help - Hello! Can someone please check and see if I did this right? Thanks...

Calculus 12th grade (double check my work please) - 1.)Find dy/dx when y= Ln (...

d/dx - d/dx( ln |sin(pi/x)| ) = ? Thanks. If those are absolute value signs, the...

Calculus grade 12 - Determine the derivative of each function A1) y = e^x(Sin²x...

Is this right - Find the derivative y=sinx(sinx+cosx) I got y'= cos(x)-sin^2(x)+...

Math (trigonometric identities) - I was given 21 questions for homework and I ...

Calculus - I have y = sin^2(3^(x)) which I rewrite as y = (sin(3^(x)))^2 I got ...

Calculus - Find the dervatives: 1. f(x)=(3x+1)e^x^2 2. y = e^(sin x) ln(x) 3. f(...