Posted by **Judy** on Thursday, May 7, 2009 at 3:54am.

I think I'm using the wrong formulas or SOMETHING... Here's the question:

"Two equal charges are separated by 3.7 ´ 10^-10 m.

The force between the charges has a magnitude of 2.37 ´ 10^-3 N. What is the magnitude of q on the charges?"

Here's my work:

F = kc(q1q2/r^2)

2.37 x 10^-3 = 8.99 x 10^9 • q1q2 / (3.7 x 10^-10)^2

F • r^2 = kc • q1q2

F • r^2 / kc = q1q2

2.37 x 10^-3 • (3.7 x 10^-10)^2 / 8.99 x 10^9 = q1q2

q1q2 = 3.61 x 10^-32

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

E = kc • q/r^2

2.37 x 10^-3 = 8.99 x 10^9 • q/(3.7 x 10^-10)^2

2.37 x 10^-3 / 8.99 x 10^9 = q/(3.7 x 10^-10)^2

2.37 x 10^-3 / 8.99 x 10^9 • (3.7 x 10^-10)^2 = q

q = 3.61 x 10^-32

PLEASE, PLEASE, PLEASE tell me what I'm doing wrong!!!

Thank you very much. :)

## Answer This Question

## Related Questions

- Physics (SO CONFUSED!!!) - I think I'm using the wrong formulas or SOMETHING... ...
- Science - Two point charges are 10.0 cm apart and have charges of 2.0 μC ...
- Physics - Two point charges are 10.0 cm apart and have charges of 2.0 μC ...
- Physics Need Help PLEASE - Two point charges are separated by 8 cm. The ...
- Physics - Two equal charges are separated by 3.7 x 10^-10 m. The force between ...
- Physics - Hi, I solved this problem, but I want to make sure it is correct: 2 ...
- physics - Two point charges are separated by 6.4 cm. The attractive force ...
- Physics - The force between two identical charges separated by 1 cm is equal to ...
- physics - two charges of equal magnitude are 25.5 cm apart if the force between ...
- physics - I have these problems that I keep doing and keep missing. If someone ...

More Related Questions