Physics (SO CONFUSED!!!)
posted by Judy on .
I think I'm using the wrong formulas or SOMETHING... Here's the question:
"Two equal charges are separated by 3.7 ´ 10^10 m.
The force between the charges has a magnitude of 2.37 ´ 10^3 N. What is the magnitude of q on the charges?"
Here's my work:
F = kc(q1q2/r^2)
2.37 x 10^3 = 8.99 x 10^9 • q1q2 / (3.7 x 10^10)^2
F • r^2 = kc • q1q2
F • r^2 / kc = q1q2
2.37 x 10^3 • (3.7 x 10^10)^2 / 8.99 x 10^9 = q1q2
q1q2 = 3.61 x 10^32
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
E = kc • q/r^2
2.37 x 10^3 = 8.99 x 10^9 • q/(3.7 x 10^10)^2
2.37 x 10^3 / 8.99 x 10^9 = q/(3.7 x 10^10)^2
2.37 x 10^3 / 8.99 x 10^9 • (3.7 x 10^10)^2 = q
q = 3.61 x 10^32
PLEASE, PLEASE, PLEASE tell me what I'm doing wrong!!!
Thank you very much. :)

Your answer is q^2
take the square root to get q
q = sqrt (3.61*10^32) = 1.9 * 10^16