Thursday

July 31, 2014

July 31, 2014

Posted by **sonia** on Wednesday, May 6, 2009 at 8:55pm.

i found the average slope to be 2.043181217

By the Mean Value Theorem, we know there exists a c in the open interval (3,10) such that f'(c) is equal to this mean slope

i tried tking the first derivative of the eq and getting x^1/2+5/x^1/2 +2.043181217

please help i dont no wut to do next?

- math -
**bobpursley**, Wednesday, May 6, 2009 at 10:46pmLets check your slope.

f'=5/sqrtx

2.043=5/sqrtx

sqrtx=2.44

x=5.97

check that.

**Related Questions**

calculus - Consider the function f(x)=–3x3–1x2+1x+1Find the average slope of ...

calculus - Consider the function f(x)=6sqrt(x)+1 on the interval [3,5] . Find ...

math - Consider the function f(x)=2sqrtx+4 on the interval [2,8]. Find the ...

math - Consider the function f(x)=–2x^3–3x^2+2x–2 Find the average slope of this...

calculus - Consider the function f(x)=4sqrtx+5 on the interval [4,5]. Find the ...

Calc, Mean Value Theorem - Consider the function : 3x^3 - 2x^2 - 4x + 1 Find the...

calc - consider the function f(x)=x^3 - x^2 - 3x -2. find the average slope of ...

Calculus - Find the average or mean slope of 2x^3 - 6x^2 - 90x +3 on the ...

CALCULUS! - Consider the function f(x)=4x^3–2x on the interval [–2,2]. Find the...

calculus - Consider the function f(x)=3x^2 – 5x on the interval [-4,4]. Find the...