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December 20, 2014

December 20, 2014

Posted by **sonia** on Wednesday, May 6, 2009 at 8:55pm.

i found the average slope to be 2.043181217

By the Mean Value Theorem, we know there exists a c in the open interval (3,10) such that f'(c) is equal to this mean slope

i tried tking the first derivative of the eq and getting x^1/2+5/x^1/2 +2.043181217

please help i dont no wut to do next?

- math -
**bobpursley**, Wednesday, May 6, 2009 at 10:46pmLets check your slope.

f'=5/sqrtx

2.043=5/sqrtx

sqrtx=2.44

x=5.97

check that.

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