Posted by Meloney on Wednesday, May 6, 2009 at 5:57pm.
A design calls for a rectangular garden with an area of 180 square feet. If the length is to be 3 feet more than the width, set up an equation and solve that equation to find the dimensions of the garden.
I drew a sketch and labeled the width "w" and the length "w+3"
my equation was:
w(w+3)=180
simplified and split the middle term:
w^2+15w12w180=0
should I group again?
thanks, meloney

Algebra 1  Emmalene, Wednesday, May 6, 2009 at 6:08pm
Hey, Mel!
Well, w^2 + 15w  12w  180 = 0.
Turns into:
w^2 + 3w  180 = 0.
Then, you can either split the middle form (take 2) or you can do the other thing (don't know how to explain it... but you know what I mean by take 1, right?)
If you need any more help, tell me. :)

Algebra 1  Meloney, Wednesday, May 6, 2009 at 6:10pm
my equation is splitting the middle term emmalene. sigh.

Algebra 1  RickP, Wednesday, May 6, 2009 at 6:14pm
w^2 + 15w  12w  180 = 0
pull out the GCF of each pair.
w(w + 15)  12(w + 15) = 0
then pull out the common factor (w + 15) from eatch term.
(w + 15)(w  12) = 0
see if you can take it from there.

Algebra 1  Meloney, Wednesday, May 6, 2009 at 6:17pm
thanks so much!!!
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