Factor the numerator and denominator of each fraction if neceesary. Rewrite each one as a product. Then look for ones and simplify. The denominator is not zero.

x^2+6x+9 2x^2-x-10 28x^2-x-15
-------- --------- ----------
x^2-9 3x^2+7x+2 28x^2-x-15

x^2+4x
-------
2x+8

very hard to figure out what you typed.

Please use brackets next time, building fractions in this format does not work.

I think you meant:
(x^2+6x+9)/(x^2-9) * (2x^2-x-10)/(x^2+7x+2) * (28x^2-x-15)/(28x^2-x-15)
I assume you know how to factor, since this is usually the type of exercise with that topic

= (x+3)(x+3)/[(x-3)(x+3)] * (2x-5)(x+2)/[(3x+1)(x+2)] * (28x^2-x-15)/(28x^2-x-15)
= (x+3)(2x-5)/[(x+3)(3x+1) , x not equal to -3,-1/3

I did not attempt to factor the last part, since it just canceled.

To factor the numerator and denominator of each fraction, we need to look for common factors that can be factored out. Let's go through each fraction one by one:

1. Fraction: (x^2+6x+9) / (x^2-9)
The numerator can be factored as (x+3)(x+3) or (x+3)^2.
The denominator can be factored as (x+3)(x-3).

So, the fraction can be rewritten as [(x+3)^2] / [(x+3)(x-3)].

2. Fraction: (2x^2 - x - 10) / (3x^2 + 7x + 2)
The numerator cannot be factored further.

The denominator can be factored as (3x+1)(x+2).

So, the fraction remains the same: (2x^2 - x - 10) / (3x+1)(x+2).

3. Fraction: (28x^2 - x - 15) / (28x^2 - x - 15)
Both the numerator and denominator are already factored.

So, the fraction remains the same: (28x^2 - x - 15) / (28x^2 - x - 15).

Now, let's simplify each fraction:

1. Simplifying the first fraction:
[(x+3)^2] / [(x+3)(x-3)]

We can cancel out the common factor of (x+3) from the numerator and denominator:

= (x+3) / (x-3)

2. Simplifying the second fraction remains the same:
(2x^2 - x - 10) / (3x+1)(x+2)

3. Simplifying the third fraction remains the same:
(28x^2 - x - 15) / (28x^2 - x - 15)

Next, let's move on to the next fraction:

Fraction: (x^2 + 4x) / (2x + 8)

The numerator can be factored as x(x + 4).

The denominator can be factored as 2(x + 4).

So, the fraction can be rewritten as (x(x + 4)) / (2(x + 4)).

Now, let's simplify this fraction:

We can cancel out the common factor of (x + 4) from the numerator and denominator:

= x / 2

Therefore, the simplified fraction (x^2 + 4x) / (2x + 8) is equivalent to x / 2.