Posted by **Kelsie** on Wednesday, May 6, 2009 at 5:36pm.

Factor the numerator and denominator of each fraction if neceesary. Rewrite each one as a product. Then look for ones and simplify. The denominator is not zero.

x^2+6x+9 2x^2-x-10 28x^2-x-15

-------- --------- ----------

x^2-9 3x^2+7x+2 28x^2-x-15

x^2+4x

-------

2x+8

- Algebra -
**Reiny**, Wednesday, May 6, 2009 at 5:56pm
very hard to figure out what you typed.

Please use brackets next time, building fractions in this format does not work.

I think you meant:

(x^2+6x+9)/(x^2-9) * (2x^2-x-10)/(x^2+7x+2) * (28x^2-x-15)/(28x^2-x-15)

I assume you know how to factor, since this is usually the type of exercise with that topic

= (x+3)(x+3)/[(x-3)(x+3)] * (2x-5)(x+2)/[(3x+1)(x+2)] * (28x^2-x-15)/(28x^2-x-15)

= (x+3)(2x-5)/[(x+3)(3x+1) , x not equal to -3,-1/3

I did not attempt to factor the last part, since it just canceled.

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