Posted by **Meloney** on Wednesday, May 6, 2009 at 5:29pm.

I also have been having some trouble with this problem. How do I set it up?

A rectangular garden is designed so that its length is twice its width. The number of feet in the perimeter of the garden is equal to the number of square feet in its area. What are the dimensions of the garden?

- Algebra 1 -
**Reiny**, Wednesday, May 6, 2009 at 5:41pm
make a sketch and label the width x, then the length must be 2x

the perimeter would be 2(x+2x) = 6x

and the area would be x(2x) = 2x^2

<<The number of feet in the perimeter of the garden is equal to the number of square feet in its area>>

6x = 2x^2

2x^2 - 6x=0

2x(x-3)=0

so x=0, not very likely or

x = 3

so the width is 3 and the length is 6

check: perimeter = 2(3+6) = 18

area = (36) = 18

ok then!

- Algebra 1 -
**Meloney**, Wednesday, May 6, 2009 at 5:43pm
thank you so much!!

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