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October 21, 2014

October 21, 2014

Posted by **Meloney** on Wednesday, May 6, 2009 at 5:29pm.

A rectangular garden is designed so that its length is twice its width. The number of feet in the perimeter of the garden is equal to the number of square feet in its area. What are the dimensions of the garden?

- Algebra 1 -
**Reiny**, Wednesday, May 6, 2009 at 5:41pmmake a sketch and label the width x, then the length must be 2x

the perimeter would be 2(x+2x) = 6x

and the area would be x(2x) = 2x^2

<<The number of feet in the perimeter of the garden is equal to the number of square feet in its area>>

6x = 2x^2

2x^2 - 6x=0

2x(x-3)=0

so x=0, not very likely or

x = 3

so the width is 3 and the length is 6

check: perimeter = 2(3+6) = 18

area = (36) = 18

ok then!

- Algebra 1 -
**Meloney**, Wednesday, May 6, 2009 at 5:43pmthank you so much!!

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